41x-0.15x^2=1200

Solution for 41x-0.15x^2=1200 equation:

41x-0.15x^2=1200

We move all terms to the left:

41x-0.15x^2-(1200)=0

a = -0.15; b = 41; c = -1200;
Δ = b2-4ac
Δ = 412-4·(-0.15)·(-1200)
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{961}=31$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(41)-31}{2*-0.15}=\frac{-72}{-0.3}
=+240
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(41)+31}{2*-0.15}=\frac{-10}{-0.3}
=33+0.1/0.3
$